A chair with four legs has a mass of 6.00 kilograms. The chair is resting upright on the ground, and a 26.0 kilogram child is standing on the chair. What is the normal force being applied by the ground to a single leg of the chair? (Assume gravitational acceleration is 9.81 meters per second squared.)
Question
A chair with four legs has a mass of 6.00 kilograms. The chair is resting upright on the ground, and a 26.0 kilogram child is standing on the chair. What is the normal force being applied by the ground to a single leg of the chair? (Assume gravitational acceleration is 9.81 meters per second squared.)
Solution
First, we need to calculate the total weight of the chair and the child. The weight is the mass of an object multiplied by the gravitational acceleration.
The weight of the chair is: 6.00 kg * 9.81 m/s^2 = 58.86 N
The weight of the child is: 26.0 kg * 9.81 m/s^2 = 255.06 N
The total weight is the sum of the weight of the chair and the child, which is: 58.86 N + 255.06 N = 313.92 N
This total weight is distributed evenly among the four legs of the chair, so the normal force on each leg is the total weight divided by four: 313.92 N / 4 = 78.48 N
So, the normal force being applied by the ground to a single leg of the chair is 78.48 N.
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