A coil has 170 turns enclosing an area of 14.0 cm2cm2 . In a physics laboratory experiment, the coil is rotated during the time interval 0.044 ss from a position in which the plane of each turn is perpendicular to Earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 6.50×10−5 TT .Part AWhat is the magnitude |Φinitial||Φinitial| of the magnetic flux through one turn of the coil before it is rotated?
Question
A coil has 170 turns enclosing an area of 14.0 cm2cm2 . In a physics laboratory experiment, the coil is rotated during the time interval 0.044 ss from a position in which the plane of each turn is perpendicular to Earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 6.50×10−5 TT .Part AWhat is the magnitude |Φinitial||Φinitial| of the magnetic flux through one turn of the coil before it is rotated?
Solution
The magnetic flux Φ through a loop is given by the equation Φ = B * A * cos(θ), where B is the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop.
Before the coil is rotated, the plane of each turn is perpendicular to Earth's magnetic field. This means that the angle θ is 0 degrees. The cosine of 0 degrees is 1.
So, the initial magnetic flux |Φ_initial| through one turn of the coil is B * A * cos(0) = B * A.
Given that the magnetic field B is 6.50×10−5 T and the area A is 14.0 cm^2 = 14.0 * 10^-4 m^2 (since 1 cm^2 = 10^-4 m^2), we can substitute these values into the equation to find the initial magnetic flux.
|Φ_initial| = B * A = 6.50×10−5 T * 14.0 * 10^-4 m^2 = 9.1 * 10^-8 Wb (Weber).
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