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A thin coil has 14 rectangular turns of wire. When a current of 1.00 A runs through the coil, there is a total flux of 0.001 T-m2 enclosed by one turn of the coil (note that the inductance is the proportionality constant between current and magnetic flux). What is the total inductance in Henries?

Question

A thin coil has 14 rectangular turns of wire. When a current of 1.00 A runs through the coil, there is a total flux of 0.001 T-m2 enclosed by one turn of the coil (note that the inductance is the proportionality constant between current and magnetic flux). What is the total inductance in Henries?

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Solution

The inductance (L) of a coil can be calculated using the formula:

L = Φ/I

where: Φ is the magnetic flux through one turn of the coil, I is the current running through the coil.

Given in the problem, Φ = 0.001 T-m2 and I = 1.00 A. Substituting these values into the formula gives:

L = 0.001 T-m2 / 1.00 A = 0.001 H

However, this is the inductance for one turn of the coil. The problem states that there are 14 turns in the coil. The total inductance for all turns is the inductance per turn multiplied by the number of turns. Therefore, the total inductance L_total is:

L_total = 14 turns * 0.001 H/turn = 0.014 H

So, the total inductance of the coil is 0.014 Henries.

This problem has been solved

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