If i is current through the circuit and E is EMF of battery then power P at which chemical energy of battery is dissipated isa.P=iEb.P=E/ic.P=Ei^2d.P=i/E
Question
If i is current through the circuit and E is EMF of battery then power P at which chemical energy of battery is dissipated isa.P=iEb.P=E/ic.P=Ei^2d.P=i/E
Solution
The power P at which the chemical energy of the battery is dissipated is given by the formula P = Ei. So, the correct answer is c. P = Ei.
Here's the step by step explanation:
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Power (P) is defined as the work done per unit time. In the context of an electrical circuit, it's the rate at which electrical energy is transferred by an electric circuit.
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The electric power in a circuit is the product of the potential difference (or EMF, E) and the current (i) flowing through it.
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Therefore, by substituting these values into the power formula, we get P = Ei.
So, the power at which the chemical energy of the battery is dissipated is directly proportional to both the EMF of the battery and the current flowing through the circuit.
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