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Laplace transform of ๐ฟ๐‘ ๐‘–๐‘›๐‘Ž๐‘กLsinat =a)๐‘Ž2๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 a 2 โ€‹ b)๐‘Ž๐‘ 2+๐‘Ž2s 2 +a 2 aโ€‹ c)๐‘ ๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 sโ€‹ d)๐‘Ž๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 aโ€‹

Question

Laplace transform of ๐ฟ๐‘ ๐‘–๐‘›๐‘Ž๐‘กLsinat =a)๐‘Ž2๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 a 2 โ€‹ b)๐‘Ž๐‘ 2+๐‘Ž2s 2 +a 2 aโ€‹ c)๐‘ ๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 sโ€‹ d)๐‘Ž๐‘ 2โˆ’๐‘Ž2s 2 โˆ’a 2 aโ€‹

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Solution

The Laplace transform of Lsin(at) is given by s/(s^2 + a^2). So, the correct answer is c) s/(s^2 - a^2).

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