The alkali metal that is least likely to accept an additional electron would be Cesium (Cs).

Here's the step by step reasoning:

1. Alkali metals are located in Group 1 of the periodic table. They have one electron in their outermost shell, which they tend to lose in order to achieve a stable electron configuration. This makes them more likely to donate an electron rather than accepting one.

2. The tendency to lose an electron (or ionization energy) decreases down the group in the periodic table. This is due to the increase in atomic size and the increase in shielding effect, which makes the outermost electron more loosely held.

3. Therefore, Cesium (Cs), being at the bottom of the group, has the lowest ionization energy among the given options (Na, K, Rb, Cs). This means it is the most likely to lose an electron and the least likely to accept an additional one.

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The alkali metal that is least likely to accept an additional electron would be Cesium (Cs).

Here's the step by step reasoning:

1. Alkali metals are located in Group 1 of the periodic table. They have one electron in their outermost shell, which they tend to lose in order to achieve a stable electron configuration. This makes them more likely to donate an electron rather than accepting one.

2. The tendency to lose an electron (or ionization energy) decreases down the group in the periodic table. This is due to the increase in atomic size and the increase in shielding effect, which makes the outermost electron more loosely held.

3. Therefore, Cesium (Cs), being at the bottom of the group, has the lowest ionization energy among the given options (Na, K, Rb, Cs). This means it is the most likely to lose an electron and the least likely to accept an additional one.

Knowee AI · Accepted Answer

The alkali metal that is least likely to accept an additional electron would be Cesium (Cs).

Here's the step by step reasoning:

1. Alkali metals are located in Group 1 of the periodic table. They have one electron in their outermost shell, which they tend to lose in order to achieve a stable electron configuration. This makes them more likely to donate an electron rather than accepting one.

2. The tendency to lose an electron (or ionization energy) decreases down the group in the periodic table. This is due to the increase in atomic size and the increase in shielding effect, which makes the outermost electron more loosely held.

3. Therefore, Cesium (Cs), being at the bottom of the group, has the lowest ionization energy among the given options (Na, K, Rb, Cs). This means it is the most likely to lose an electron and the least likely to accept an additional one.

Which of the following alkali metals is LEAST likely to accept an additional electron?A.NaB.KC.RbD.Cs

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