To find the normal force experienced by a 3 kg box placed on a rigid floor, we can follow these steps:

1. Identify the forces acting on the box: In this case, the only force acting on the box is the force due to gravity, which is equal to the weight of the box.

2. Calculate the weight of the box: The weight of an object can be calculated using the formula: weight = mass x acceleration due to gravity. In this case, the mass of the box is 3 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the box is 3 kg x 9.8 m/s^2 = 29.4 N.

3. Determine the direction of the normal force: The normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface. In this case, since the box is placed on a rigid floor, the normal force will act vertically upwards.

4. Apply Newton's third law: According to Newton's third law of motion, the normal force exerted by the floor on the box is equal in magnitude and opposite in direction to the weight of the box. Therefore, the normal force experienced by the box is also 29.4 N, but in the upward direction.

So, the normal force experienced by the 3 kg box placed on a rigid floor is 29.4 N, acting vertically upwards.

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To find the normal force experienced by a 3 kg box placed on a rigid floor, we can follow these steps:

1. Identify the forces acting on the box: In this case, the only force acting on the box is the force due to gravity, which is equal to the weight of the box.

2. Calculate the weight of the box: The weight of an object can be calculated using the formula: weight = mass x acceleration due to gravity. In this case, the mass of the box is 3 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the box is 3 kg x 9.8 m/s^2 = 29.4 N.

3. Determine the direction of the normal force: The normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface. In this case, since the box is placed on a rigid floor, the normal force will act vertically upwards.

4. Apply Newton's third law: According to Newton's third law of motion, the normal force exerted by the floor on the box is equal in magnitude and opposite in direction to the weight of the box. Therefore, the normal force experienced by the box is also 29.4 N, but in the upward direction.

So, the normal force experienced by the 3 kg box placed on a rigid floor is 29.4 N, acting vertically upwards.

Knowee AI · Accepted Answer

To find the normal force experienced by a 3 kg box placed on a rigid floor, we can follow these steps:

1. Identify the forces acting on the box: In this case, the only force acting on the box is the force due to gravity, which is equal to the weight of the box.

2. Calculate the weight of the box: The weight of an object can be calculated using the formula: weight = mass x acceleration due to gravity. In this case, the mass of the box is 3 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the box is 3 kg x 9.8 m/s^2 = 29.4 N.

3. Determine the direction of the normal force: The normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface. In this case, since the box is placed on a rigid floor, the normal force will act vertically upwards.

4. Apply Newton's third law: According to Newton's third law of motion, the normal force exerted by the floor on the box is equal in magnitude and opposite in direction to the weight of the box. Therefore, the normal force experienced by the box is also 29.4 N, but in the upward direction.

So, the normal force experienced by the 3 kg box placed on a rigid floor is 29.4 N, acting vertically upwards.

Find the normal force experienced by a 3 kg box placed on a rigid floor.

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