Find the normal force experienced by a block of mass 6 kg placed on the rigid elevator floor, accelerating upward by  3m/s23m/s 2 .

To find the normal force experienced by the block, we need to consider the forces acting on it.

Step 1: Identify the forces acting on the block. In this case, we have the force of gravity (weight) pulling the block downward and the normal force pushing the block upward.

Step 2: Determine the weight of the block. The weight of an object can be calculated using the formula: weight = mass × acceleration due to gravity. In this case, the mass of the block is given as 6 kg. The acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the block is 6 kg × 9.8 m/s^2 = 58.8 N.

Step 3: Determine the net force acting on the block. The net force is the vector sum of all the forces acting on the block. In this case, the net force is equal to the mass of the block multiplied by its acceleration. The mass of the block is 6 kg and the acceleration is given as 3 m/s^2. Therefore, the net force is 6 kg × 3 m/s^2 = 18 N.

Step 4: Apply Newton's second law of motion. According to Newton's second law, the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force is 18 N and the mass is 6 kg. Therefore, the acceleration of the block is 18 N / 6 kg = 3 m/s^2.

Step 5: Determine the normal force. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal in magnitude and opposite in direction to the weight of the block. Therefore, the normal force is 58.8 N, which is equal to the weight of the block.

So, the normal force experienced by the block is 58.8 N.