Consider the nuclear reaction X200 → A110 + B90, If the binding energy per nucleon for X, A and B is 7.4 MeV, 8.2 MeV and 8.2 MeV respectively, what is the energy released-200 MeV160 MeV110 MeV90 MeV
Question
Consider the nuclear reaction X200 → A110 + B90, If the binding energy per nucleon for X, A and B is 7.4 MeV, 8.2 MeV and 8.2 MeV respectively, what is the energy released-200 MeV160 MeV110 MeV90 MeV
Solution
To solve this problem, we need to calculate the total binding energy before and after the reaction and then find the difference.
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Calculate the total binding energy before the reaction: The total binding energy for X is given by the product of the number of nucleons and the binding energy per nucleon. For X, this is 200 nucleons * 7.4 MeV/nucleon = 1480 MeV.
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Calculate the total binding energy after the reaction: The total binding energy for A is 110 nucleons * 8.2 MeV/nucleon = 902 MeV. The total binding energy for B is 90 nucleons * 8.2 MeV/nucleon = 738 MeV. Adding these together gives a total of 902 MeV + 738 MeV = 1640 MeV.
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Find the difference: The energy released is the difference in total binding energy before and after the reaction. This is 1640 MeV - 1480 MeV = 160 MeV.
So, the energy released is 160 MeV.
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