The half-life of 30P is 2.50 minutes. If a sample of 30P has 1.60 × 1010 nuclei present initially, how many remain after 10.0 minutes?Scegli un'alternativa:A.0.050 × 1010B.0.400 × 1010C.D.0.800 × 1010E.0.100 × 1010
Question
The half-life of 30P is 2.50 minutes. If a sample of 30P has 1.60 × 1010 nuclei present initially, how many remain after 10.0 minutes?Scegli un'alternativa:A.0.050 × 1010B.0.400 × 1010C.D.0.800 × 1010E.0.100 × 1010
Solution
To solve this problem, we first need to understand what half-life means. Half-life is the time required for half of a sample to decay.
Given that the half-life of 30P is 2.50 minutes, this means that every 2.50 minutes, half of the remaining 30P nuclei will decay.
We are asked to find out how many nuclei remain after 10.0 minutes.
10.0 minutes is 4 half-lives (10.0 minutes / 2.5 minutes/half-life = 4 half-lives).
We start with 1.60 x 10^10 nuclei and every half-life we have half as many nuclei left.
After 1 half-life (2.5 minutes), we have 1.60 x 10^10 / 2 = 0.80 x 10^10 nuclei. After 2 half-lives (5.0 minutes), we have 0.80 x 10^10 / 2 = 0.40 x 10^10 nuclei. After 3 half-lives (7.5 minutes), we have 0.40 x 10^10 / 2 = 0.20 x 10^10 nuclei. After 4 half-lives (10.0 minutes), we have 0.20 x 10^10 / 2 = 0.10 x 10^10 nuclei.
So, the answer is E. 0.100 x 10^10.
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