To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

Given in the problem, we have:

N0 = 490 μg,
t = 31.7 days, and
T = 24.1 days.

Substituting these values into the formula, we get:

N = 490 μg * (1/2)^(31.7 days / 24.1 days).

Now, we just need to calculate the value of N.

(1/2)^(31.7 days / 24.1 days) = 0.403

So, N = 490 μg * 0.403 = 197.47 μg.

Rounding to the nearest whole number, we get 197 μg. So, after 31.7 days, there will be approximately 197 μg of the isotope 234Th left.

Question

To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

Given in the problem, we have:

N0 = 490 μg,
t = 31.7 days, and
T = 24.1 days.

Substituting these values into the formula, we get:

N = 490 μg * (1/2)^(31.7 days / 24.1 days).

Now, we just need to calculate the value of N.

(1/2)^(31.7 days / 24.1 days) = 0.403

So, N = 490 μg * 0.403 = 197.47 μg.

Rounding to the nearest whole number, we get 197 μg. So, after 31.7 days, there will be approximately 197 μg of the isotope 234Th left.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

N is the final amount of the substance,
N0 is the initial amount of the substance,
t is the time that has passed, and
T is the half-life of the substance.

Given in the problem, we have:

N0 = 490 μg,
t = 31.7 days, and
T = 24.1 days.

Substituting these values into the formula, we get:

N = 490 μg * (1/2)^(31.7 days / 24.1 days).

Now, we just need to calculate the value of N.

(1/2)^(31.7 days / 24.1 days) = 0.403

So, N = 490 μg * 0.403 = 197.47 μg.

Rounding to the nearest whole number, we get 197 μg. So, after 31.7 days, there will be approximately 197 μg of the isotope 234Th left.

A 490. μg sample of the isotope 234Th is prepared. How much is left after 31.7 days? The half-life of 234Th is 24.1 days. 307 μg 59.0 μg 197 μg 147 μg Tries 0/2

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