The following code gives this incorrect output.Which of the following statements about what is causing the error is true? (select all valid answers)carrie@ubuntu:/debugging$ cat main.c #include <stdio.h> /** * main - debugging example * Return: 0 */ int main(void) { int i; int j; for (i = 0; i < 10; i++) { j = 0; while (j < 10) { printf("%d", j); } printf("\n"); } return (0); } carrie@ubuntu:/debugging$carrie@ubuntu:/debugging$ gcc -Wall -Werror -Wextra -pedantic main.c carrie@ubuntu:/debugging$ ./a.out0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 <...>^Ccarrie@ubuntu:/debugging$j never increments so it will always be less than 10j never increments so it is always going to print 0j is always equal to i so the loop will never endI don't know
Question
The following code gives this incorrect output.Which of the following statements about what is causing the error is true? (select all valid answers)carrie@ubuntu:/debugging cat main.c #include <stdio.h> /** * main - debugging example * Return: 0 */ int main(void) { int i; int j; for (i = 0; i < 10; i++) { j = 0; while (j < 10) { printf("%d", j); } printf("\n"); } return (0); } carrie@ubuntu:/debuggingcarrie@ubuntu:/debugging ./a.out0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 <...>^Ccarrie@ubuntu:/debugging$j never increments so it will always be less than 10j never increments so it is always going to print 0j is always equal to i so the loop will never endI don't know
Solution
Based on the given code, the incorrect output is caused by the fact that the variable "j" is not being incremented inside the inner while loop. This means that "j" will always be 0, causing an infinite loop and printing only 0 repeatedly. Therefore, the statement "j never increments so it is always going to print 0" is true.
Similar Questions
The following code gives this incorrect output.Which of the following statements about what is causing the error is true? (select all valid answers)carrie@ubuntu:/debugging$ cat main.c #include <stdio.h> /** * main - debugging example * Return: 0 */ int main(void) { int i; int j; for (i = 0; i < 10; i++) { j = 0; while (j < 10) { printf("%d", j); } printf("\n"); } return (0); } carrie@ubuntu:/debugging$carrie@ubuntu:/debugging$ gcc -Wall -Werror -Wextra -pedantic main.c carrie@ubuntu:/debugging$ ./a.out0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 <...>^Ccarrie@ubuntu:/debugging$j never increments so it will always be less than 10j never increments so it is always going to print 0j is always equal to i so the loop will never endI don't know
why the above 2 lines of code is incorrect:
Which of the following is an invalid specifier for the printf statement? %4c You Answered %10b %6d Correct answer %8.2d %10.2e
Select the correct answerWhich of the following is an invalid variable?Optionscode_tantra_1code_1code_tantra
Write down the reasons of the following invalid variable names:
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