Ramesh and Suresh start driving from the same place simultaneously in two different cars towards north and west directions respectively. Ramesh's car moves with uniform speed and crosses a road-side mango tree after driving for exactly 7 minutes. The speed of Suresh's car was 32 kmph. After 45 minutes the straight line distance between the two cars is 51 km. What is the distance between Suresh's car and the mango tree after 45 minutes from the starting time?
Question
Ramesh and Suresh start driving from the same place simultaneously in two different cars towards north and west directions respectively. Ramesh's car moves with uniform speed and crosses a road-side mango tree after driving for exactly 7 minutes. The speed of Suresh's car was 32 kmph. After 45 minutes the straight line distance between the two cars is 51 km. What is the distance between Suresh's car and the mango tree after 45 minutes from the starting time?
Solution
The problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as: a² + b² = c².
Step 1: Calculate the distance Suresh's car has traveled. Suresh's car travels at a speed of 32 km/h. In 45 minutes, the car would have traveled a distance of (32 km/h * 45/60 h) = 24 km.
Step 2: Calculate the distance Ramesh's car has traveled. We know that the straight line distance between the two cars after 45 minutes is 51 km. Using the Pythagorean theorem, we can calculate the distance Ramesh's car has traveled as follows: Let's denote the distance Ramesh's car has traveled as 'd'. Then we have: d² + 24² = 51² Solving this equation for 'd' gives: d = sqrt(51² - 24²) = 45 km.
Step 3: Calculate the speed of Ramesh's car. Ramesh's car crosses a road-side mango tree after driving for exactly 7 minutes. Therefore, the speed of Ramesh's car is (45 km / 45 min) * 60 min/h = 60 km/h.
Step 4: Calculate the distance between Suresh's car and the mango tree. The distance between Suresh's car and the mango tree is the distance Ramesh's car has traveled in 45 minutes minus the distance it has traveled in 7 minutes. This is because the mango tree is located 7 minutes away from the starting point in the direction Ramesh's car is traveling. Therefore, the distance between Suresh's car and the mango tree is (45 km - (60 km/h * 7/60 h)) = 45 km - 7 km = 38 km.
So, the distance between Suresh's car and the mango tree after 45 minutes from the starting time is 38 km.
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