How many times will the condition (current >=0) be checked in this loop? int total = 0;int current = 6;while ( current >= 0 ) { int next = 0; while ( next < 10) { total = total + next; next = next + 1; } total = total * current; current = current - 2;}

The condition (current >= 0) will be checked 4 times in this loop. Here's the step-by-step explanation:

1. Initially, the value of 'current' is 6. So, the condition (current >= 0) is checked for the first time and it's true.

2. After the first iteration of the outer loop, 'current' is decreased by 2, making it 4. The condition (current >= 0) is checked for the second time and it's still true.

3. After the second iteration of the outer loop, 'current' is decreased by 2 again, making it 2. The condition (current >= 0) is checked for the third time and it's still true.

4. After the third iteration of the outer loop, 'current' is decreased by 2 once more, making it 0. The condition (current >= 0) is checked for the fourth time and it's still true.

5. After the fourth iteration of the outer loop, 'current' is decreased by 2 again, making it -2. The condition (current >= 0) is checked for the fifth time and this time it's false. So, the loop terminates.

So, the condition (current >= 0) is checked 4 times when it's true and 1 time when it's false, making a total of 5 checks. But if you're only counting the times when the condition is true (i.e., when the loop actually runs), then it's checked 4 times.