A pitot-static tube is .used to measure air velocity. If a manometer" connected to theinstrument indicates a difference in pressure head between the tappings of 3.0mm of water,calculate the air velocity assuining the coefficient of the pitôt tube to be 0.95, Density of air= 1.2Kg/m.
Question
A pitot-static tube is .used to measure air velocity. If a manometer" connected to theinstrument indicates a difference in pressure head between the tappings of 3.0mm of water,calculate the air velocity assuining the coefficient of the pitôt tube to be 0.95, Density of air= 1.2Kg/m.
Solution
To calculate the air velocity using a Pitot-static tube, we can use the Bernoulli's equation which is given by:
V = sqrt((2*(ΔP))/ρ)
Where: V = velocity of the air ΔP = difference in pressure ρ = density of the air
Given: ΔP = 3.0 mm of water = 3.0 * 9.81 * 10^-3 N/m² (since 1mm of water = 9.81 * 10^-3 N/m²) ρ = 1.2 kg/m³ Coefficient of the Pitot tube = 0.95
Substituting the given values into the equation, we get:
V = sqrt((2*(3.0 * 9.81 * 10^-3))/1.2)
After calculating the above expression, we get the velocity of the air. However, since we are given a coefficient of the Pitot tube, we need to multiply our result by this coefficient to get the actual air velocity.
So, the actual air velocity V_actual = V * Coefficient of the Pitot tube
V_actual = V * 0.95
This will give you the air velocity assuming the coefficient of the Pitot tube to be 0.95.
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