Knowee
Questions
Features
Study Tools

A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The reverse recovery current is given as 0.5A and the reverse recovery time is given as 100ns with the maximum reverse blocking voltage as 400V.  The on-off switching loss is computed as: Select one:a. 0.5 Wb. None of the given choicesc. 2 Wd. 1 Watt

Question

A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The reverse recovery current is given as 0.5A and the reverse recovery time is given as 100ns with the maximum reverse blocking voltage as 400V.  The on-off switching loss is computed as: Select one:a. 0.5 Wb. None of the given choicesc. 2 Wd. 1 Watt

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The question is asking for the on-off switching loss of a Schottky diode in a power converter. Here are the steps to calculate it:

  1. First, we need to calculate the average current. The peak-to-peak current is 20A, and the duty cycle is 60%. So, the average current is 20A * 60% = 12A.

  2. Next, we calculate the power loss during the on state. This is given by the product of the forward voltage drop and the average current, which is 0.3V * 12A = 3.6W.

  3. Then, we calculate the power loss during the off state. This is given by the product of the reverse recovery current and the maximum reverse blocking voltage, which is 0.5A * 400V = 200W.

  4. The total power loss is the sum of the on state power loss and the off state power loss, which is 3.6W + 200W = 203.6W.

  5. However, the power loss is not constant. It occurs only during the switching period, which is given by the reverse recovery time. So, we need to multiply the total power loss by the switching frequency and the reverse recovery time to get the average power loss over time. This is 203.6W * 100kHz * 100ns = 2.036W.

  6. Finally, we round the result to the nearest whole number to get the final answer. So, the on-off switching loss is approximately 2W.

Therefore, the correct answer is c. 2 W.

This problem has been solved

Similar Questions

A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The conduction loss in Watts would be: .

A typical reverse recovery time @ dIF/dt = 25A  and 25 degree Celsius for a fast diode  VS-70HFL is given as 500 ns and a typical reverse recovered charge is given as 1300 nC. If the off-state reverse voltage in certain application is 540 Volts and the operating frequency is 20kHz. The switching power loss in Watts is given as approximately:Select one:a. 4b. 7c. 5d. 10

A Schottky diode carrying current (If) of 10A with forward voltage drop (Vf) of 0.2V is used in a power converter. If the diode has junction to ambient thermal resistance Rth_ja = 40 deg.C/W and operating at ambient temperature Ta = 20 deg.C. Calculate the junction temperature (Tj) accounting only for conduction losses in degrees Celsius.... Select one:a. 80b. 120c. 140d. 100

Fom the piece-wise model of a diode we get: Dynamic resistance (rd) of the diode is 50 mΩ and knee voltage (vd) is 0.6V. This diode is connected in series with a 40V square wave voltage source (min=0V, max=40V, Duty ratio=0.25) and 20Ω resistance (RL). ON state power loss for the diode approximately is ____________ W.Select one:a. 0.35b. 1.4c. 1d. 0.8e. None of the Above

What should be the absolute value of the peak reverse current (approximate) in Ampere to recover the stored charge during the changeover from forward conduction to reverse blocking condition of a diode?, if  Stored charge is 10uC and the reverse recovery time of a diode is 5us.Select one:a. 2b. None of the abovec. 8d. 1e. 4

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.