A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The conduction loss in Watts would be: .
Question
A Schottky diode carrying current of Square wave @ 20A PK-PK @ duty cycle of 60% and a frequency of 100kHz with a forward voltage drop (Vf) of 0.3V is used in a power converter. The conduction loss in Watts would be: .
Solution
To calculate the conduction loss in a Schottky diode, we can use the formula:
P = Iavg * Vf
Where:
- P is the power loss
- Iavg is the average current
- Vf is the forward voltage drop
Given:
- The peak-to-peak current (Ipp) is 20A
- The duty cycle is 60% or 0.6
- The forward voltage drop (Vf) is 0.3V
First, we need to calculate the average current (Iavg). For a square wave, the average current over a period is given by the peak current times the duty cycle.
Iavg = Ipp * Duty Cycle Iavg = 20A * 0.6 = 12A
Then, we can substitute Iavg and Vf into the power loss formula:
P = Iavg * Vf P = 12A * 0.3V = 3.6W
So, the conduction loss in the Schottky diode is 3.6 Watts.
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