class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: dummyHead = ListNode(0) tail = dummyHead carry = 0 while l1 is not None or l2 is not None or carry != 0: digit1 = l1.val if l1 is not None else 0 digit2 = l2.val if l2 is not None else 0 sum = digit1 + digit2 + carry digit = sum % 10 carry = sum // 10 newNode = ListNode(digit) tail.next = newNode tail = tail.next l1 = l1.next if l1 is not None else None l2 = l2.next if l2 is not None else None result = dummyHead.next dummyHead.next = None return result
Question
class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: dummyHead = ListNode(0) tail = dummyHead carry = 0 while l1 is not None or l2 is not None or carry != 0: digit1 = l1.val if l1 is not None else 0 digit2 = l2.val if l2 is not None else 0 sum = digit1 + digit2 + carry digit = sum % 10 carry = sum // 10 newNode = ListNode(digit) tail.next = newNode tail = tail.next l1 = l1.next if l1 is not None else None l2 = l2.next if l2 is not None else None result = dummyHead.next dummyHead.next = None return result
Solution
This is a Python solution for adding two numbers represented by linked lists. Here's a step-by-step explanation:
-
The class
Solutionis defined with a methodaddTwoNumbersthat takes two linked lists (l1andl2) as input. -
A dummy head node is created to keep track of the head of the result linked list.
-
A
whileloop is used to iterate through the linked lists until both lists are exhausted and there is no carry left from the previous addition. -
In each iteration, the values of the current nodes of
l1andl2are added together with the carry from the previous addition. If a list is exhausted, its value is considered as 0. -
The sum is then split into the digit (sum modulo 10) and the carry (sum divided by 10).
-
A new node is created with the digit and appended to the result linked list.
-
The current nodes of
l1andl2are moved to the next nodes. If a list is exhausted, it remainsNone. -
After the loop, the head of the result linked list is detached from the dummy head and returned as the result.
This solution assumes that the input linked lists represent non-negative integers, where each node contains a single digit and the digits are stored in reverse order.
Similar Questions
2. Add Two NumbersMedium29K5.6KCompaniesYou are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.You may assume the two numbers do not contain any leading zero, except the number 0 itself. Example 1:Input: l1 = [2,4,3], l2 = [5,6,4]Output: [7,0,8]Explanation: 342 + 465 = 807.
class Solution(object): def plusOne(self, digits): digits=digits[::-1] if digits[0]==9: digits[0]=10 else: digits[0]=digits[0]+1 digits=digits[::-1] return digits
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.You may assume the two numbers do not contain any leading zero, except the number 0 itsel
Write a function that adds 2 integers.Prototype: def add_integer(a, b=98):a and b must be integers or floats, otherwise raise a TypeError exception with the message a must be an integer or b must be an integera and b must be first casted to integers if they are floatReturns an integer: the addition of a and bYou are not allowed to import any module
ou are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.