class Solution(object): def plusOne(self, digits): digits=digits[::-1] if digits[0]==9: digits[0]=10 else: digits[0]=digits[0]+1 digits=digits[::-1] return digits
Question
class Solution(object): def plusOne(self, digits): digits=digits[::-1] if digits[0]==9: digits[0]=10 else: digits[0]=digits[0]+1 digits=digits[::-1] return digits
Solution
The code you've provided is written in Python and it's a method to increment the last digit of a number represented as a list of digits. However, it seems like there's a mistake in the code. If the last digit is 9, it's replaced with 10 which is not correct. Here's the corrected version:
class Solution(object):
def plusOne(self, digits):
for i in range(len(digits)-1, -1, -1):
if digits[i] == 9:
digits[i] = 0
else:
digits[i] += 1
return digits
return [1] + digits
Here's how it works:
- The function starts from the last digit of the number (the least significant digit).
- If the digit is not 9, it increments the digit by 1 and returns the number.
- If the digit is 9, it sets the digit to 0 and continues to the next digit.
- If all digits are 9, it adds a 1 at the beginning of the number.
Similar Questions
class Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode: dummyHead = ListNode(0) tail = dummyHead carry = 0 while l1 is not None or l2 is not None or carry != 0: digit1 = l1.val if l1 is not None else 0 digit2 = l2.val if l2 is not None else 0 sum = digit1 + digit2 + carry digit = sum % 10 carry = sum // 10 newNode = ListNode(digit) tail.next = newNode tail = tail.next l1 = l1.next if l1 is not None else None l2 = l2.next if l2 is not None else None result = dummyHead.next dummyHead.next = None return result
class Myclass: x=0 def incre(self): self.x+=1 def disp(self): print(self.x)ob1=Myclass()ob1.incre()ob1.disp()ob2=Myclass()ob2.incre()ob2.disp()0 01 21101
A number consists of two digits and the digit in the ten’s place exceeds that in the unit’s place by 5. if 5 times the sum of the digits be added from the numbers, the digits of the number are reversed. Then the sum of digits of the number is?
A number consists of two digits and the digit in the ten’s place exceeds that in the unit’s place by 5. if 5 times the sum of the digits be added from the numbers, the digits of the number are reversed. Then the sum of digits of the number is?Options91116137
class Demo: def __init__(self): self.a = 1 self.__b = 1 def get(self): return self.__bobj = Demo()obj.a=45print(obj.a)
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