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A man walks forward on a bus. To a stationary observer, the bus moves east at a speed of 18 m/s. If the man moves 1.5 m/s east relative to the bus, what is his velocity in the frame of reference of a stationary observer?A.18 m/s eastB.16.5 m/s eastC.19.5 m/s eastD.16.5 m/s westSUBMITarrow_backPREVIOUS

Question

A man walks forward on a bus. To a stationary observer, the bus moves east at a speed of 18 m/s. If the man moves 1.5 m/s east relative to the bus, what is his velocity in the frame of reference of a stationary observer?A.18 m/s eastB.16.5 m/s eastC.19.5 m/s eastD.16.5 m/s westSUBMITarrow_backPREVIOUS

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Solution

The velocity of the man relative to the stationary observer is the sum of the velocity of the bus and the velocity of the man relative to the bus.

The bus is moving east at 18 m/s and the man is also moving east relative to the bus at 1.5 m/s.

So, the total velocity of the man relative to the stationary observer is 18 m/s + 1.5 m/s = 19.5 m/s east.

Therefore, the correct answer is C. 19.5 m/s east.

This problem has been solved

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