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A motor scooter travels east at a speed of 11.6 m/s. The driver then reverses direction and heads west at 17.2 m/s. What is the change in velocity of the scooter? Give magnitude (enter first) and direction. (east or west?)

Question

A motor scooter travels east at a speed of 11.6 m/s. The driver then reverses direction and heads west at 17.2 m/s. What is the change in velocity of the scooter? Give magnitude (enter first) and direction. (east or west?)

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Solution

The change in velocity is calculated by subtracting the initial velocity from the final velocity.

Here, the initial velocity is 11.6 m/s to the east. When we consider direction, we can denote this as +11.6 m/s.

The final velocity is 17.2 m/s to the west. In terms of direction, we can denote this as -17.2 m/s.

So, the change in velocity (Δv) is final velocity (v_f) minus initial velocity (v_i), or Δv = v_f - v_i.

Substituting the given values, we get Δv = -17.2 m/s - (+11.6 m/s) = -28.8 m/s.

The negative sign indicates the direction, which is west.

So, the magnitude of the change in velocity is 28.8 m/s and the direction is west.

This problem has been solved

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