A motor scooter travels east at a speed of 11.6 m/s. The driver then reverses direction and heads west at 17.2 m/s. What is the change in velocity of the scooter? Give magnitude (enter first) and direction. (east or west?)
Question
A motor scooter travels east at a speed of 11.6 m/s. The driver then reverses direction and heads west at 17.2 m/s. What is the change in velocity of the scooter? Give magnitude (enter first) and direction. (east or west?)
Solution
The change in velocity is calculated by subtracting the initial velocity from the final velocity.
Here, the initial velocity is 11.6 m/s to the east. When we consider direction, we can denote this as +11.6 m/s.
The final velocity is 17.2 m/s to the west. In terms of direction, we can denote this as -17.2 m/s.
So, the change in velocity (Δv) is final velocity (v_f) minus initial velocity (v_i), or Δv = v_f - v_i.
Substituting the given values, we get Δv = -17.2 m/s - (+11.6 m/s) = -28.8 m/s.
The negative sign indicates the direction, which is west.
So, the magnitude of the change in velocity is 28.8 m/s and the direction is west.
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