A slab of glass has a 0.800 cm thick layer of water on top of it. A light ray strikes the water at an incident angle of 64.0°. At what angle does the light ray travel through the glass? 1.27 rad 0.642 rad 0.237 rad 1.40 rad

To solve this problem, we need to use Snell's Law, which states that the ratio of the sine of the angles of incidence and transmission is equivalent to the ratio of the indices of refraction.

The formula for Snell's Law is: n1sin(θ1) = n2sin(θ2)

Where: n1 and θ1 are the refractive index and angle of incidence in the first medium, n2 and θ2 are the refractive index and angle of transmission in the second medium.

Given: n1 (refractive index of water) = 1.33, θ1 (angle of incidence in water) = 64.0°, n2 (refractive index of glass) = 1.52.

We need to find θ2 (angle of transmission in glass).

First, convert the angle of incidence from degrees to radians because the trigonometric functions in most calculators use radians.

θ1 = 64.0° * (π/180) = 1.117 radians.

Then, plug the known values into Snell's Law and solve for θ2:

1.33sin(1.117) = 1.52sin(θ2)

Solving for θ2 gives:

θ2 = arcsin[(1.33*sin(1.117))/1.52]

Calculate the value to get the angle of transmission in the glass.

Please note that the answer will be in radians.