The problem involves the use of Snell's law and the fact that the reflected and refracted rays are perpendicular to each other.

Step 1: Given that the reflected and refracted rays are perpendicular to each other, the angle of refraction (r) is 90 degrees.

Step 2: The refractive index of the glass slab (n) is given as 33.

Step 3: We can use Snell's law, which states that the ratio of the sine of the angle of incidence (i) to the sine of the angle of refraction (r) is equal to the refractive index. In mathematical terms, this is expressed as:

n = sin(i) / sin(r)

Step 4: Substituting the given values into the equation, we get:

33 = sin(i) / sin(90)

Step 5: Since sin(90) is 1, the equation simplifies to:

33 = sin(i)

Step 6: To find the angle of incidence (i), we need to find the inverse sine (also known as arcsin or sin^-1) of 33.

Please note that the refractive index cannot be greater than 1 for real materials in physics. The

Question

The problem involves the use of Snell's law and the fact that the reflected and refracted rays are perpendicular to each other.

Step 1: Given that the reflected and refracted rays are perpendicular to each other, the angle of refraction (r) is 90 degrees.

Step 2: The refractive index of the glass slab (n) is given as 33​.

Step 3: We can use Snell's law, which states that the ratio of the sine of the angle of incidence (i) to the sine of the angle of refraction (r) is equal to the refractive index. In mathematical terms, this is expressed as:

n = sin(i) / sin(r)

Step 4: Substituting the given values into the equation, we get:

33​ = sin(i) / sin(90)

Step 5: Since sin(90) is 1, the equation simplifies to:

33​ = sin(i)

Step 6: To find the angle of incidence (i), we need to find the inverse sine (also known as arcsin or sin^-1) of 33​.

Please note that the refractive index cannot be greater than 1 for real materials in physics. The

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