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What will be the result of the following code snippet?int main() {    int *ptr1, *ptr2;    ptr1 = (int *)malloc(sizeof(int));    ptr2 = (int *)malloc(sizeof(int));    *ptr1 = 42;    *ptr2 = *ptr1;    free(ptr1);    printf("%d\n", *ptr2);    free(ptr2);    return 0;}

Question

What will be the result of the following code snippet?int main() {    int *ptr1, *ptr2;    ptr1 = (int *)malloc(sizeof(int));    ptr2 = (int *)malloc(sizeof(int));    *ptr1 = 42;    *ptr2 = *ptr1;    free(ptr1);    printf("%d\n", *ptr2);    free(ptr2);    return 0;}

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Solution

The result of the code snippet will be "42".

Here's the step by step explanation:

  1. Two pointers, ptr1 and ptr2, are declared.
  2. Memory is allocated for these two pointers using the malloc function. The size of the memory allocated is the size of an integer.
  3. The value 42 is assigned to the memory location pointed to by ptr1.
  4. The value in the memory location pointed to by ptr1 (which is 42) is assigned to the memory location pointed to by ptr2.
  5. The memory allocated to ptr1 is freed using the free function. This does not affect the value of *ptr2 because the value was copied before ptr1 was freed.
  6. The value in the memory location pointed to by ptr2 (which is 42) is printed.
  7. The memory allocated to ptr2 is freed.
  8. The program returns 0, indicating successful execution.

This problem has been solved

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