A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Question
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Solution
First, let's find out how much work A, B, and C can do in a day.
A can do 1/20 of the work in a day. B can do 1/30 of the work in a day. C can do 1/60 of the work in a day.
Now, let's find out how much work A, B, and C can do together in three days.
On the first two days, only A is working. So, in two days, A can do 2 * (1/20) = 1/10 of the work.
On the third day, A, B, and C are all working. So, in one day, they can do (1/20) + (1/30) + (1/60) = 1/10 of the work.
So, in three days, A, B, and C can do 1/10 + 1/10 = 1/5 of the work.
Therefore, to complete the whole work, it would take them 5 * 3 = 15 days. However, remember that on every third day, A is assisted by B and C. So, in 15 days, A is assisted by B and C for 15/3 = 5 days.
So, A alone would take 15 - 5 = 10 days to complete the work.
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