, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Question
, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Solution
The problem is about work and time, and it involves three people: A, B, and C. Here are the steps to solve it:
Step 1: Find the one day's work of B, C, and (B+C) together. B's one day work = 1/20 C's one day work = 1/30 (B+C)'s one day work = 1/20 + 1/30 = 1/12
Step 2: Find the work done by A, B, and C in the first three days. In the first two days, only A works, and on the third day, B and C assist A. So, the work done in the first three days is: 2*(A's one day work) + (B+C)'s one day work
Step 3: Set up an equation to solve for A's one day work. We know that the work done in three days is 1/12 of the total work. So, we can set up the following equation: 2*(A's one day work) + 1/12 = 1/12
Step 4: Solve the equation for A's one day work. Solving the equation, we get A's one day work = 0
This means that A cannot complete the work by himself, even with the assistance of B and C every third day.
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