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An object weighs 10 N in air. When fully immersed in water, it weighs only 8 N. The weight of the liquid displaced by the object will be:

Question

An object weighs 10 N in air. When fully immersed in water, it weighs only 8 N. The weight of the liquid displaced by the object will be:

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Solution

The weight of the liquid displaced by the object can be determined using Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.

Here are the steps to find the weight of the liquid displaced:

  1. Determine the weight of the object in air. In this case, it's given as 10 N.

  2. Determine the apparent weight of the object when it's fully immersed in water. In this case, it's given as 8 N.

  3. Subtract the weight of the object in water from its weight in air to find the buoyant force, which is also the weight of the water displaced by the object.

So, 10 N (weight in air) - 8 N (weight in water) = 2 N.

Therefore, the weight of the water displaced by the object is 2 N.

This problem has been solved

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