The sum of five consecutive even numbers is equal to 260. what is the sum of the largest number amongst them and the half the square of the smallest numbers amongst them?Options16441274134612881208

The problem states that the sum of five consecutive even numbers is 260.

Step 1: Find the average of the numbers. Since they are consecutive even numbers, the average will be the middle number. So, 260/5 = 52.

Step 2: Identify the smallest and largest numbers. Since 52 is the middle number, the smallest number will be 52 - 22 = 48 and the largest number will be 52 + 22 = 56.

Step 3: Calculate half the square of the smallest number. (48^2)/2 = 1152.

Step 4: Add the largest number to half the square of the smallest number. 1152 + 56 = 1208.

So, the sum of the largest number amongst them and half the square of the smallest numbers amongst them is 1208.