The bullet fired from a gun on the ground has a velocity v. The x-component of the velocity is 7.2 ms-1 and the y-component of the velocity is 9 ms-1. x is the horizontal axis and y is the vertial axis. What is the distance in m between the gun and the point where the bullet hits the ground? Acceleration due to gravity is 9.8ms-2. Assuming there is no air resistance during the bullet's flight.

To solve this problem, we need to find the time the bullet is in the air and then use that time to find the horizontal distance the bullet travels.

1. First, we find the time the bullet is in the air. The bullet is in the air for the time it takes to rise and fall. We can find the time it takes to rise by using the equation of motion: v = u + at, where v is the final velocity (which is 0 at the highest point), u is the initial velocity (which is the y-component of the velocity, 9 m/s), and a is the acceleration (which is -9.8 m/s² due to gravity). Solving for t gives us t = (v - u) / a = (0 - 9) / -9.8 = 0.918 seconds. The bullet takes the same amount of time to fall, so the total time in the air is 2 * 0.918 = 1.836 seconds.

2. Next, we find the horizontal distance the bullet travels. The horizontal distance is the horizontal velocity times the time in the air. The horizontal velocity is the x-component of the velocity, 7.2 m/s. So the horizontal distance is 7.2 m/s * 1.836 s = 13.22 meters.

So, the distance between the gun and the point where the bullet hits the ground is 13.22 meters.

To solve this problem, we need to find the time the bullet is in the air and then use that to find the horizontal distance it travels.

1. First, we find the time the bullet is in the air. The bullet is in the air as long as it takes to reach its peak and then fall back to the ground. The time to reach the peak can be found by using the equation of motion: v = u + at, where v is the final velocity (0 m/s at the peak), u is the initial velocity (9 m/s), and a is the acceleration (-9.8 m/s², the negative sign indicates that gravity is acting downwards). Solving for t gives us t = (v - u) / a = (0 - 9) / -9.8 = 0.918 seconds. The total time in the air is twice this (going up and coming down), so t = 2 * 0.918 = 1.836 seconds.

2. Next, we find the horizontal distance the bullet travels. The horizontal velocity is constant (7.2 m/s), so the horizontal distance (d) can be found by multiplying the horizontal velocity by the time in the air: d = vt = 7.2 m/s * 1.836 s = 13.22 m.

So, the distance between the gun and the point where the bullet hits the ground is approximately 13.22 meters.