The output of the given Python code will be:

6
6

Here's the step-by-step explanation:

1. The initial value of `n` is 7 and `c` is 0.
2. The `while` loop will continue as long as `n` is not 0.
3. Inside the loop, it checks if `n` is greater than 5. If it is, it adds `n-1` to `c` and decreases `n` by 1. So, in the first iteration, `c` becomes 6 (7-1) and `n` becomes 6.
4. In the next iteration, `n` is not greater than 5, so it breaks out of the loop.
5. Finally, it prints the values of `n` and `c`, which are 6 and 6 respectively.

Question

The output of the given Python code will be:

6
6

Here's the step-by-step explanation:

1. The initial value of `n` is 7 and `c` is 0.
2. The `while` loop will continue as long as `n` is not 0.
3. Inside the loop, it checks if `n` is greater than 5. If it is, it adds `n-1` to `c` and decreases `n` by 1. So, in the first iteration, `c` becomes 6 (7-1) and `n` becomes 6.
4. In the next iteration, `n` is not greater than 5, so it breaks out of the loop.
5. Finally, it prints the values of `n` and `c`, which are 6 and 6 respectively.

Knowee AI · Accepted Answer

The output of the given Python code will be:

6
6

Here's the step-by-step explanation:

1. The initial value of `n` is 7 and `c` is 0.
2. The `while` loop will continue as long as `n` is not 0.
3. Inside the loop, it checks if `n` is greater than 5. If it is, it adds `n-1` to `c` and decreases `n` by 1. So, in the first iteration, `c` becomes 6 (7-1) and `n` becomes 6.
4. In the next iteration, `n` is not greater than 5, so it breaks out of the loop.
5. Finally, it prints the values of `n` and `c`, which are 6 and 6 respectively.

What will be the output of the given Python code?n=7c=0while(n): if(n > 5): c=c+n-1 n=n-1 else: breakprint(n)print(c)

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