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A rectangular floor of dimensions 3m 40cm and 5m 20cm is to be covered with identical square tiles. Find the minimum number of square tiles required428432436440442

Question

A rectangular floor of dimensions 3m 40cm and 5m 20cm is to be covered with identical square tiles. Find the minimum number of square tiles required428432436440442

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Solution

To find the minimum number of square tiles required to cover the floor, we first need to find the greatest common divisor (GCD) of the length and width of the floor. The GCD will give us the side length of the square tile that will cover the floor without leaving any space.

Step 1: Convert the dimensions of the floor to the same units. Here, we convert meters to centimeters because the measurements are given in a mix of meters and centimeters. So, 3m 40cm = 340cm and 5m 20cm = 520cm.

Step 2: Find the GCD of 340cm and 520cm. The GCD of 340 and 520 is 20. So, the side length of each square tile is 20cm.

Step 3: Calculate the number of tiles required. The area of the floor is 340cm * 520cm = 176800 square cm. The area of each tile is 20cm * 20cm = 400 square cm.

Step 4: Divide the total area of the floor by the area of each tile to get the number of tiles required. So, 176800 / 400 = 442.

Therefore, a minimum of 442 square tiles are required to cover the floor.

This problem has been solved

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