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Range of Motion (m) 50°- Trial 1: 8.5 inches- Trial 2: 14.2 inches- Trial 3: 7 inchesSolve the problem by using a set angle to identify the average rate of the projection of the ball

Question

Range of Motion (m) 50°- Trial 1: 8.5 inches- Trial 2: 14.2 inches- Trial 3: 7 inchesSolve the problem by using a set angle to identify the average rate of the projection of the ball

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Solution 1

To solve this problem, we first need to calculate the average projection of the ball. This can be done by adding the results of the three trials and dividing by the number of trials.

Step 1: Add the results of the three trials 8.5 inches (Trial 1) + 14.2 inches (Trial 2) + 7 inches (Trial 3) = 29.7 inches

Step 2: Divide the total by the number of trials to get the average 29.7 inches / 3 trials = 9.9 inches

So, the average projection of the ball is 9.9 inches.

However, the problem also mentions a "set angle" and "range of motion", but does not provide enough information on how these factors are to be incorporated into the calculation. If the angle or range of motion were to affect the projection, we would need additional information on how they do so.

This problem has been solved

Solution 2

To solve this problem, we first need to understand that the range of motion (m) is given as 50°. This is the angle at which the ball is projected. The distances covered in each trial are 8.5 inches, 14.2 inches, and 7 inches respectively.

The average rate of projection can be calculated by finding the average distance covered in the three trials.

Step 1: Add up the distances of the three trials 8.5 inches (Trial 1) + 14.2 inches (Trial 2) + 7 inches (Trial 3) = 29.7 inches

Step 2: Divide the total distance by the number of trials to find the average distance 29.7 inches / 3 trials = 9.9 inches/trial

Therefore, the average rate of the projection of the ball at a set angle of 50° is 9.9 inches per trial.

This problem has been solved

Solution 3

To solve this problem, we first need to find the average distance the ball was projected. This can be done by adding up the distances from each trial and dividing by the number of trials.

Step 1: Add up the distances from each trial 8.5 inches (Trial 1) + 14.2 inches (Trial 2) + 7 inches (Trial 3) = 29.7 inches

Step 2: Divide the total distance by the number of trials to find the average distance 29.7 inches / 3 trials = 9.9 inches

This means that on average, the ball was projected 9.9 inches.

However, to find the average rate of the projection of the ball, we need more information such as the time it took for each projection. The rate is typically distance over time. Without a time component, we can't calculate the rate.

If you're looking for the average distance the ball was projected, that would be 9.9 inches.

This problem has been solved

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