A ball is thrown with speed of 29.4m/s at an angle of 30 o above the horizontal. The total time taken to cover the horizontal range is:a.8sb.3sc.4sd.6s
Question
A ball is thrown with speed of 29.4m/s at an angle of 30 o above the horizontal. The total time taken to cover the horizontal range is:a.8sb.3sc.4sd.6s
Solution
The total time of flight for a projectile launched at an angle θ with an initial speed v is given by the formula:
t = 2v*sin(θ) / g
where: v = initial speed θ = launch angle g = acceleration due to gravity (approximately 9.8 m/s²)
First, we need to convert the launch angle from degrees to radians. In radians, 30 degrees is equivalent to π/6.
Then we can plug in the given values:
t = 229.4 m/ssin(π/6) / 9.8 m/s² t = 58.8 m/s * 0.5 / 9.8 m/s² t = 29.4 m / 9.8 s² t = 3 s
Therefore, the total time taken to cover the horizontal range is 3 seconds.
The correct answer is:
b. 3s
Similar Questions
Range of Motion (m) 50°- Trial 1: 8.5 inches- Trial 2: 14.2 inches- Trial 3: 7 inchesSolve the problem by using a set angle to identify the average rate of the projection of the ball
How high would a ball go if it is thrown vertically upward and returns to launching position after 8 seconds?*1 pointA. 7.84 mB. 31.36 mC..78.4 mD. 313.6 m
A ball is projected straight up with an initial velocity of 20 m/s. After 0.3 seconds its velocity will be Question 7Answera.0 m/sb.-20 m/sc.22.94 m/sd.20 m/se.17.06 m/s
Given the same initial velocity, at what other angle should a ball be hit to reach the same distance if it is being shot at an angle of 30° and it reaches a distance of 50 m?
A body is projected downward at an angle of 30° to the horizontal with a velocity of 9.8 m/s from the top of a tower 29.4 m high. How long will it take before striking the ground?A 2 s B 5 s C 8 s D 10 s
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.