To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert all temperatures to Kelvin. The Kelvin scale starts at absolute zero, which is -273.15°C. So, 25°C = 25 + 273.15 = 298.15 K and -23°C = -23 + 273.15 = 250.15 K.

Step 2: Substitute the known values into the formula. We know that V1 = 0.85 L, T1 = 298.15 K, and T2 = 250.15 K. We're trying to find V2, the final volume of the balloon.

0.85 L / 298.15 K = V2 / 250.15 K

Step 3: Solve for V2.

V2 = (0.85 L / 298.15 K) * 250.15 K = 0.71 L

So, the final volume of the balloon when it is placed in the deep freeze is approximately 0.71 L.

Question

To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert all temperatures to Kelvin. The Kelvin scale starts at absolute zero, which is -273.15°C. So, 25°C = 25 + 273.15 = 298.15 K and -23°C = -23 + 273.15 = 250.15 K.

Step 2: Substitute the known values into the formula. We know that V1 = 0.85 L, T1 = 298.15 K, and T2 = 250.15 K. We're trying to find V2, the final volume of the balloon.

0.85 L / 298.15 K = V2 / 250.15 K

Step 3: Solve for V2.

V2 = (0.85 L / 298.15 K) * 250.15 K = 0.71 L

So, the final volume of the balloon when it is placed in the deep freeze is approximately 0.71 L.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert all temperatures to Kelvin. The Kelvin scale starts at absolute zero, which is -273.15°C. So, 25°C = 25 + 273.15 = 298.15 K and -23°C = -23 + 273.15 = 250.15 K.

Step 2: Substitute the known values into the formula. We know that V1 = 0.85 L, T1 = 298.15 K, and T2 = 250.15 K. We're trying to find V2, the final volume of the balloon.

0.85 L / 298.15 K = V2 / 250.15 K

Step 3: Solve for V2.

V2 = (0.85 L / 298.15 K) * 250.15 K = 0.71 L

So, the final volume of the balloon when it is placed in the deep freeze is approximately 0.71 L.

A 0.85 L latex balloon at 25°C is placed in a deep freeze at -23 °C. What will be the final volume of the balloon?

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