A particular balloon has a volume of 4.50 L at a temperature of 21.5oC. What will its volume be if it is cooled in a freezer to –4.0oC?Multiple choice question.4.11 L2.25 L4.93 L0.837 L
Question
A particular balloon has a volume of 4.50 L at a temperature of 21.5oC. What will its volume be if it is cooled in a freezer to –4.0oC?Multiple choice question.4.11 L2.25 L4.93 L0.837 L
Solution
This question can be solved using the Charles's Law formula, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming pressure is constant. The formula is V1/T1 = V2/T2.
First, convert the temperatures from Celsius to Kelvin. The Kelvin scale starts at -273.15 degrees Celsius.
T1 = 21.5°C + 273.15 = 294.65 K T2 = -4.0°C + 273.15 = 269.15 K
The initial volume, V1, is 4.50 L. We need to find the final volume, V2.
Rearrange the formula to solve for V2: V2 = V1 * (T2/T1)
V2 = 4.50 L * (269.15 K / 294.65 K) = 4.11 L
So, the volume of the balloon when it is cooled to -4.0°C will be approximately 4.11 L. Therefore, the correct answer is 4.11 L.
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