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YouA police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance he will catch the thief

Question

YouA police chases a thief. Their respective speeds are 8 and 6 km/hr. If the police started 10 min late, at what distance he will catch the thief

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Solution

Sure, here is the step by step solution:

  1. First, we need to convert the 10 minutes into hours because the speed is given in km/hr. So, 10 minutes = 10/60 = 0.1667 hours.

  2. In this 0.1667 hours, the thief has already covered a distance. We can find this distance by multiplying the time by the speed of the thief. So, the distance = speed * time = 6 km/hr * 0.1667 hr = 1 km.

  3. Now, the police starts chasing the thief. The relative speed of the police with respect to the thief is the difference of their speeds, which is 8 km/hr - 6 km/hr = 2 km/hr.

  4. The police will catch the thief when he covers the 1 km distance. We can find the time it takes for the police to cover this distance by dividing the distance by the speed. So, time = distance / speed = 1 km / 2 km/hr = 0.5 hours.

  5. To find the distance at which the police catches the thief, we multiply the time by the speed of the police. So, the distance = speed * time = 8 km/hr * 0.5 hr = 4 km.

So, the police will catch the thief at a distance of 4 km.

This problem has been solved

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