A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is
Question
A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is
Solution
First, we need to understand that the policeman is running faster than the thief. The policeman runs 2 km/h faster than the thief (10 km/h - 8 km/h = 2 km/h).
The thief is 1250 m ahead of the policeman, which is 1.25 km (since 1 km = 1000 m).
The time it takes for the policeman to catch the thief can be found by dividing the distance between them by the difference in their speeds. So, 1.25 km / 2 km/h = 0.625 hours.
Finally, to find the distance run by the thief before he is nabbed, we multiply the time by the thief's speed. So, 0.625 hours * 8 km/h = 5 km.
Therefore, the thief runs 5 km before he is nabbed by the policeman.
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