The resistance of a cell filled with 0.02 N NaCl at 25° C is 210 ohms and itsspecific conductance is 0.002768 S cm-1. The cell was then washed out andthen filled with N/10 solution of ZnSO4 and its resistance was found to be38.1 ohms. Calculate equivalent conductance of ZnSO
Question
The resistance of a cell filled with 0.02 N NaCl at 25° C is 210 ohms and itsspecific conductance is 0.002768 S cm-1. The cell was then washed out andthen filled with N/10 solution of ZnSO4 and its resistance was found to be38.1 ohms. Calculate equivalent conductance of ZnSO
Solution
To calculate the equivalent conductance of ZnSO4, we can use the formula:
Equivalent Conductance (Λ) = (Specific Conductance (κ) * Cell Constant (K)) / Resistance (R)
Step 1: Calculate the specific conductance (κ) of the N/10 solution of ZnSO4. Given: Specific conductance of NaCl solution (κ1) = 0.002768 S cm-1 Cell constant of NaCl solution (K1) = 210 ohms Resistance of NaCl solution (R1) = 210 ohms
κ1 = κ1 * K1 / R1 κ1 = 0.002768 S cm-1 * 210 ohms / 210 ohms κ1 = 0.002768 S cm-1
Step 2: Calculate the resistance (R2) of the N/10 solution of ZnSO4. Given: Resistance of ZnSO4 solution (R2) = 38.1 ohms
Step 3: Calculate the equivalent conductance (Λ) of ZnSO4. Λ = κ1 * K2 / R2 Λ = 0.002768 S cm-1 * K2 / 38.1 ohms
Therefore, to calculate the equivalent conductance of ZnSO4, we need to know the cell constant (K2) of the cell filled with the N/10 solution of ZnSO4.
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