To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 3.81 years and T = 12.3 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(3.81/12.3)

Calculating this gives us approximately 0.716 or 71.6%. Therefore, about 71.6% of the sample would be left after 3.81 years. However, the problem asks us to round our answer to two significant digits, so the final answer is 72%.

Question

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 3.81 years and T = 12.3 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(3.81/12.3)

Calculating this gives us approximately 0.716 or 71.6%. Therefore, about 71.6% of the sample would be left after 3.81 years. However, the problem asks us to round our answer to two significant digits, so the final answer is 72%.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where:
- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 3.81 years and T = 12.3 years. Plugging these values into the formula gives us:

N/N0 = (1/2)^(3.81/12.3)

Calculating this gives us approximately 0.716 or 71.6%. Therefore, about 71.6% of the sample would be left after 3.81 years. However, the problem asks us to round our answer to two significant digits, so the final answer is 72%.

Hydrogen-3 is radioactive and has a half life of 12.3 years. What percentage of a sample would be left after 3.81 years?Round your answer to 2 significant digits.

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