To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 108 years and T = 28.8 years.

So, we can substitute these values into the formula:

N/N0 = (1/2)^(108/28.8)

This simplifies to:

N/N0 = (1/2)^(3.75)

Calculating this gives:

N/N0 ≈ 0.066

To express this as a percentage, we multiply by 100, giving us approximately 6.6%.

So, after 108 years, approximately 6.6% of the Strontium-90 sample would remain.

Question

To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 108 years and T = 28.8 years.

So, we can substitute these values into the formula:

N/N0 = (1/2)^(108/28.8)

This simplifies to:

N/N0 = (1/2)^(3.75)

Calculating this gives:

N/N0 ≈ 0.066

To express this as a percentage, we multiply by 100, giving us approximately 6.6%.

So, after 108 years, approximately 6.6% of the Strontium-90 sample would remain.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for exponential decay which is N = N0 * (1/2)^(t/T), where:

- N is the final amount of the substance
- N0 is the initial amount of the substance
- t is the time that has passed
- T is the half-life of the substance

In this case, we want to find N/N0, the fraction of the substance that remains after time t. We know that t = 108 years and T = 28.8 years.

So, we can substitute these values into the formula:

N/N0 = (1/2)^(108/28.8)

This simplifies to:

N/N0 = (1/2)^(3.75)

Calculating this gives:

N/N0 ≈ 0.066

To express this as a percentage, we multiply by 100, giving us approximately 6.6%.

So, after 108 years, approximately 6.6% of the Strontium-90 sample would remain.

Strontium-90 is radioactive and has a half life of 28.8 years. What percentage of a sample would be left after 108. years?Round your answer to 2 significant digits.

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