The problem can be solved using the mirror formula and the magnification formula.

The mirror formula is 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.

The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the height of the image, and h is the height of the object.

Given that the object and image heights are equal, the magnification m is 1. This means that v = -u, or the image distance is equal to the object distance but with a negative sign (since it's a real image formed by a concave mirror).

Substituting v = -u into the mirror formula gives 1/f = 1/(-u) + 1/u = 0, which implies that the focal length f is infinite.

However, the radius of curvature R of a mirror is twice its focal length (R = 2f). Since the focal length is infinite, the radius of curvature would also be infinite.

Therefore, none of the given options (A: 3 cm, B: 5 cm, C: 10 cm, D: 15 cm) is correct. The problem might have a mistake or missing information.

Question

The problem can be solved using the mirror formula and the magnification formula.

The mirror formula is 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.

The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the height of the image, and h is the height of the object.

Given that the object and image heights are equal, the magnification m is 1. This means that v = -u, or the image distance is equal to the object distance but with a negative sign (since it's a real image formed by a concave mirror).

Substituting v = -u into the mirror formula gives 1/f = 1/(-u) + 1/u = 0, which implies that the focal length f is infinite.

However, the radius of curvature R of a mirror is twice its focal length (R = 2f). Since the focal length is infinite, the radius of curvature would also be infinite.

Therefore, none of the given options (A: 3 cm, B: 5 cm, C: 10 cm, D: 15 cm) is correct. The problem might have a mistake or missing information.

Knowee AI · Accepted Answer

The problem can be solved using the mirror formula and the magnification formula.

The mirror formula is 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.

The magnification formula is m = -v/u = h'/h, where m is the magnification, h' is the height of the image, and h is the height of the object.

Given that the object and image heights are equal, the magnification m is 1. This means that v = -u, or the image distance is equal to the object distance but with a negative sign (since it's a real image formed by a concave mirror).

Substituting v = -u into the mirror formula gives 1/f = 1/(-u) + 1/u = 0, which implies that the focal length f is infinite.

However, the radius of curvature R of a mirror is twice its focal length (R = 2f). Since the focal length is infinite, the radius of curvature would also be infinite.

Therefore, none of the given options (A: 3 cm, B: 5 cm, C: 10 cm, D: 15 cm) is correct. The problem might have a mistake or missing information.

An object of height 3 cm is placed in front of a concave mirror at 10 cm. If the height of the image is also 3 cm, then radius of curvature of the mirror isA 3 cm B 5 cm C 10 cm D 15 cm

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