What is the total number of rectangular tiles required to cover a floor that measures 1010 feet 66 inches in length and 1313 feet in width? Assume that each tile measures one foot by one and a half feet.

To solve this problem, we first need to convert all measurements to the same unit. In this case, we'll convert everything to feet.

1. Convert the length of the floor to feet: The floor is 1010 feet 66 inches long. Since 1 foot is equal to 12 inches, 66 inches is equal to 66/12 = 5.5 feet. So, the total length of the floor in feet is 1010 + 5.5 = 1015.5 feet.

2. The width of the floor is already given in feet, which is 1313 feet.

3. Now, we need to find the area of the floor in square feet. The area of a rectangle (which the floor is) is given by the formula length x width. So, the area of the floor is 1015.5 feet x 1313 feet = 1333299.5 square feet.

4. Each tile measures 1 foot by 1.5 feet, so the area of each tile is 1 foot x 1.5 feet = 1.5 square feet.

5. To find the total number of tiles required, we divide the total area of the floor by the area of each tile. So, the number of tiles required is 1333299.5 square feet / 1.5 square feet/tile = 888866 tiles.

Therefore, you would need 888866 rectangular tiles to cover the floor.