A study measured heart rate per minute in two groups of people.Data is presented in the following table.GroupHeart rate/minute164, 62, 64, 61, 66, 70, 73, 61, 59, 66, 67, 68, 66, 71272, 76, 72, 71, 69, 68, 78, 75, 76, 74, 77, 78, 79, 82, 88Calculate the mean for both group 1 and group 2.Enter your answer in the text box below.

The table below contains pulse rates after running for 1 minute, collected from a sample of females who drink alcohol. The mean pulse rate after running for 1 minute of females who do not drink is 97 beats per minute. Do the data show that the mean pulse rate of females who do drink alcohol is higher than the mean pulse rate of females who do not drink? Test at the 2% level.pulse rate after running one minute in bpm57124122110801107998667080124649780701094185621189575140107671313796131159421141079896P: Parameter     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: Hypotheses     Fill in the correct null and alternative hypotheses:𝐻0: bpm 𝐻𝐴: bpm A:  Assumptions     Since information was collected from each object, what conditions do we need to check?     Check all that apply.    outliers in the data𝑛≥30 or normal population𝑁≥20𝑛𝑛(𝑝̂)≥10σσ is unknownσσ is known𝑛𝑝≥10𝑛(1-𝑝)≥10no outliers in the data𝑛(1-𝑝̂)≥10     Check those assumptions:     1. Is the value of 𝜎 known?      2. Which of the following is the correct modified boxplot?         20406080100120140160pulse rate after running one minute in bpm377096135.5159[Graphs generated by this script: setBorder(15); initPicture(20,160,-3,6);axes(20,100,1,null,null,1,'off');text([81,-3],"pulse rate after running one minute in bpm");line([37,2],[37,4]); rect([70,2],[135.5,4]); line([96,2],[96,4]);line([159,2],[159,4]); line([37,3],[70,3]); line([135.5,3],[159,3]);fontsize*=.8;fontfill='blue';text([37,4],'37','above');text([70,4],'70','above');text([96,4],'96','above');text([135.5,4],'135.5','above');text([159,4],'159','above');fontfill='black';fontsize*=1.25;]20406080100120140160pulse rate after running one minute in bpm377096112159[Graphs generated by this script: setBorder(15); initPicture(20,160,-3,6);axes(20,100,1,null,null,1,'off');text([81,-3],"pulse rate after running one minute in bpm");line([37,2],[37,4]); rect([70,2],[112,4]); line([96,2],[96,4]);line([159,2],[159,4]); line([37,3],[70,3]); line([112,3],[159,3]);fontsize*=.8;fontfill='blue';text([37,4],'37','above');text([70,4],'70','above');text([96,4],'96','above');text([112,4],'112','above');text([159,4],'159','above');fontfill='black';fontsize*=1.25;]20406080100120140160pulse rate after running one minute in bpm377083112159[Graphs generated by this script: setBorder(15); initPicture(20,160,-3,6);axes(20,100,1,null,null,1,'off');text([81,-3],"pulse rate after running one minute in bpm");line([37,2],[37,4]); rect([70,2],[112,4]); line([83,2],[83,4]);line([159,2],[159,4]); line([37,3],[70,3]); line([112,3],[159,3]);fontsize*=.8;fontfill='blue';text([37,4],'37','above');text([70,4],'70','above');text([83,4],'83','above');text([112,4],'112','above');text([159,4],'159','above');fontfill='black';fontsize*=1.25;]20406080100120140160pulse rate after running one minute in bpm3753.596112159[Graphs generated by this script: setBorder(15); initPicture(20,160,-3,6);axes(20,100,1,null,null,1,'off');text([81,-3],"pulse rate after running one minute in bpm");line([37,2],[37,4]); rect([53.5,2],[112,4]); line([96,2],[96,4]);line([159,2],[159,4]); line([37,3],[53.5,3]); line([112,3],[159,3]);fontsize*=.8;fontfill='blue';text([37,4],'37','above');text([53.5,4],'53.5','above');text([96,4],'96','above');text([112,4],'112','above');text([159,4],'159','above');fontfill='black';fontsize*=1.25;]          Are there any outliers?      3. 𝑛 = which is           Is it reasonable to assume the population is normally distributed?  N: Name the test     The conditions are met to use a .T: Test Statistic     The symbol and value of the random variable on this problem are as follows:     = bpm     The test statistic formula set up with numbers is as follows:     Round values to 2 decimal places. 𝑡=𝑋¯-𝜇𝑠𝑛=(( - ) / / ))      The final answer for the test statistic from technology is as follows:     Round to 2 decimal places.     t = O: Obtain the P-value     Report the final answer to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: Make a decision     Since the p-value , we .S: State a conclustion     There significant evidence to conclude bpm

(a) Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? (b) In 2.00 y? (c) In 2.000 y?

How do you calculate heart rate in beats per minute (bpm) using the pulse? Count the number of beats in 15 seconds and multiply by four Count the number of beats in 30 seconds and multiply by two Count the number of beats in 10 seconds and multiply by six Count the number of beats in 20 seconds and multiply by three

Heather recorded her heart rate (in beats per minute) after working out for several workouts. The rates were 124, 135, 124, 132, 82, 131, and 138 beats per minute, respectively. Which of the following is the best representation of Heather's typical heart rate after working out?Group of answer choices124 beats per minute123 beats per minute132 beats per minute125 beats per minute131 beats per minute

Here is some data of a few patient's pulse measurement: 1) Find the mean of a variable "pulse rate". Find the standard deviation of a variable "pulse rate" Use the correct symbol and choose the correct formula from the list. Plug in numbers, you don't have actually to calculate it. The correct answer is 14.2227 bpm. What would be unusually high and unusually low pulse rate?