A 12 V battery is connected across a load having a resistance of 40Ω. Determine the current flowing in the load, the power consumed and the energy dissipated in 2 minut

Sure, let's solve this step by step:

1. Determine the current flowing in the load:

We can use Ohm's law to find the current. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. It is usually formulated as V = IR, where V is the voltage, I is the current, and R is the resistance.

Rearranging for I gives us I = V/R.

Substituting the given values, we get I = 12V / 40Ω = 0.3A.

So, the current flowing in the load is 0.3 Amperes.

2. Determine the power consumed:

Power (P) in an electrical circuit is given by the product of voltage (V) and current (I), i.e., P = VI.

Substituting the given values, we get P = 12V * 0.3A = 3.6W.

So, the power consumed by the load is 3.6 Watts.

3. Determine the energy dissipated in 2 minutes:

Energy (E) is the product of power (P) and time (t), i.e., E = Pt.

However, the time needs to be in seconds for the units to work out, so first convert 2 minutes to seconds: 2 minutes = 120 seconds.

Substituting the given values, we get E = 3.6W * 120s = 432 Joules.

So, the energy dissipated in the load over 2 minutes is 432 Joules.