A 5 resistor is connected across a battery of 6 volts.Calculate the energy that dissipates as heat in 10 s

Sure, to calculate the energy that dissipates as heat in a resistor, we first need to find the current flowing through the resistor using Ohm's law.

Step 1: Calculate the current (I) using Ohm's law Ohm's law states that I = V/R, where V is the voltage and R is the resistance. So, I = 6V / 5Ω = 1.2A

Step 2: Calculate the power (P) dissipated in the resistor The power dissipated in a resistor is given by P = I^2 * R, where I is the current and R is the resistance. So, P = (1.2A)^2 * 5Ω = 7.2W

Step 3: Calculate the energy (E) dissipated as heat in the resistor The energy dissipated is given by E = P * t, where P is the power and t is the time. So, E = 7.2W * 10s = 72J

Therefore, the energy that dissipates as heat in the 5Ω resistor connected across a 6V battery in 10 seconds is 72 Joules.