To solve this problem, we first need to determine how many half-lives have passed in 48.4 days.

1. Calculate the number of half-lives:
Number of half-lives = Total time / Half-life time
Number of half-lives = 48.4 days / 14.3 days = 3.38 half-lives

2. Calculate the remaining percentage:
The remaining percentage of a radioactive substance after n half-lives can be calculated using the formula (1/2)^n.

Remaining percentage = (1/2) ^ 3.38 = 0.104 or 10.4%

So, approximately 10.4% of the Phosphorus-32 sample would be left after 48.4 days.

Question

To solve this problem, we first need to determine how many half-lives have passed in 48.4 days.

1. Calculate the number of half-lives:
   Number of half-lives = Total time / Half-life time
   Number of half-lives = 48.4 days / 14.3 days = 3.38 half-lives

2. Calculate the remaining percentage:
   The remaining percentage of a radioactive substance after n half-lives can be calculated using the formula (1/2)^n.

Remaining percentage = (1/2) ^ 3.38 = 0.104 or 10.4%

So, approximately 10.4% of the Phosphorus-32 sample would be left after 48.4 days.

Knowee AI · Accepted Answer

To solve this problem, we first need to determine how many half-lives have passed in 48.4 days.

1. Calculate the number of half-lives:
   Number of half-lives = Total time / Half-life time
   Number of half-lives = 48.4 days / 14.3 days = 3.38 half-lives

2. Calculate the remaining percentage:
   The remaining percentage of a radioactive substance after n half-lives can be calculated using the formula (1/2)^n.

Remaining percentage = (1/2) ^ 3.38 = 0.104 or 10.4%

So, approximately 10.4% of the Phosphorus-32 sample would be left after 48.4 days.

Phosphorus-32 is radioactive and has a half life of 14.3 days. What percentage of a sample would be left after 48.4 days?Round your answer to 2 significant digits.

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