A satellite of mass 600kg in a circular orbit is at a height of 2000m above the earth's surface. Taking the radius of the earth to be 6400km And the value of g to be 1N/Kg the satellites K. E is

To find the satellite's kinetic energy (K.E.), we can use the formula:

K.E. = (1/2) * m * v^2

where m is the mass of the satellite and v is its velocity.

Step 1: Calculate the radius of the satellite's orbit. The height of the satellite above the Earth's surface is given as 2000m. Since the radius of the Earth is given as 6400km, we need to convert the height to kilometers: 2000m = 2km

The radius of the satellite's orbit is then the sum of the Earth's radius and the height above the surface: Radius = 6400km + 2km = 6402km

Step 2: Calculate the velocity of the satellite. The velocity of a satellite in a circular orbit can be calculated using the formula:

v = √(g * r)

where g is the acceleration due to gravity and r is the radius of the orbit.

Given that g = 1N/Kg and the radius is 6402km (converted to meters), we can calculate the velocity: v = √(1 * 6402000) = √6402000 = 2533.29 m/s

Step 3: Calculate the kinetic energy. Now that we have the mass of the satellite (600kg) and its velocity (2533.29 m/s), we can substitute these values into the formula for kinetic energy:

K.E. = (1/2) * m * v^2 = (1/2) * 600 * (2533.29)^2 = 1.52 * 10^9 Joules

Therefore, the satellite's kinetic energy is approximately 1.52 * 10^9 Joules.