Knowee
Questions
Features
Study Tools

Radius of the orbit of Geo statimary satellite of mass m is r, If mass of the earth is M and theradius is R, the total energy of the satellite at the orbit is,

Question

Radius of the orbit of Geo statimary satellite of mass m is r, If mass of the earth is M and theradius is R, the total energy of the satellite at the orbit is,

🧐 Not the exact question you are looking for?Go ask a question

Solution

The total energy of a satellite in orbit is given by the formula:

E = -GMm/2r

Where: E is the total energy of the satellite, G is the gravitational constant, M is the mass of the Earth, m is the mass of the satellite, and r is the radius of the orbit.

The radius of the orbit for a geostationary satellite is given by:

r = (GMt^2/4π^2)^(1/3)

Where: t is the period of the satellite (which is 24 hours for a geostationary satellite).

Substituting the second equation into the first gives the total energy of a geostationary satellite in terms of G, M, m, and t:

E = -GMm/2((GMt^2/4π^2)^(1/3))

This simplifies to:

E = -GMm/(2^(4/3)(GMt^2/4π^2)^(1/3))

This is the total energy of a geostationary satellite in orbit around the Earth.

This problem has been solved

Similar Questions

Consider the two satellites A and B an earth orbit. Satellite A has a mass m , an orbital radius of r and a totalorbital energy of E. Satellite B has a mass of 4m and an orbital radius r/2. What is the orbital energy of satelliteB?(1) E (2) 2E (3) 4E (4) 8E (5) 16E

A geostationary satellite is in a circular orbit around the Earth. What is the radius of the orbit of the satellite?

A satellite of mass 600kg in a circular orbit is at a height of 2000m above the earth's surface. Taking the radius of the earth to be 6400km And the value of g to be 1N/Kg the satellites K. E is

The gravitational field strength at the surface of a planet of radius R is g . A satelliteis moving in a circular orbit a distance R above the surface of the planet. What is themagnitude of the acceleration of the satellite

If a body of mass m has to be taken from the surface to the earth to a height h = R, then the amount of energy required is (R = radius of the earth)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.