A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 2.1 × 10-5 M in calcium ion and 4.75 × 10-5 M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC2O4) = 2.3 × 10-9.Group of answer choicesNothing will happen since calcium oxalate is extremely soluble.A precipitate will form since Q > Ksp for calcium oxalate.Nothing will happen since Ksp > Q for all possible precipitants.Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.
Question
A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 2.1 × 10-5 M in calcium ion and 4.75 × 10-5 M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC2O4) = 2.3 × 10-9.Group of answer choicesNothing will happen since calcium oxalate is extremely soluble.A precipitate will form since Q > Ksp for calcium oxalate.Nothing will happen since Ksp > Q for all possible precipitants.Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.
Solution
To determine what will happen when these solutions are mixed, we need to calculate the reaction quotient (Q) and compare it to the solubility product constant (Ksp) for calcium oxalate.
The reaction quotient Q is given by the product of the concentrations of the ions in the solution. In this case, Q = [Ca2+][C2O42-] = (2.1 × 10-5 M)(4.75 × 10-5 M) = 9.975 × 10-10.
The Ksp for calcium oxalate is given as 2.3 × 10-9.
Comparing Q and Ksp, we see that Q > Ksp. This means that the solution is supersaturated with respect to calcium oxalate, and a precipitate will form. Therefore, the correct answer is "A precipitate will form since Q > Ksp for calcium oxalate."
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