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The mean price of a sample of mid-range computer graphics cards at the beginning of 2020 was $150. The mean price of an independent sample of mid-range cards at the beginning of 2021 was $185. If the pooled variance of the samples was 36, approximately what is the corresponding Cohen's effect size? 0.97 30.8 5.83 5.14

Question

The mean price of a sample of mid-range computer graphics cards at the beginning of 2020 was 150.Themeanpriceofanindependentsampleofmidrangecardsatthebeginningof2021was150. The mean price of an independent sample of mid-range cards at the beginning of 2021 was 185. If the pooled variance of the samples was 36, approximately what is the corresponding Cohen's effect size? 0.97 30.8 5.83 5.14

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Solution

Cohen's d is a measure of effect size that represents the magnitude of differences between two means in standard deviation units. It is calculated as the difference between two means divided by the pooled standard deviation.

The formula for Cohen's d is:

d = (M2 - M1) / SDpooled

where: M1 = mean of group 1 M2 = mean of group 2 SDpooled = pooled standard deviation

Given in the problem: M1 = 150M2=150 M2 = 185 SDpooled = sqrt(36) = 6

Substituting these values into the formula gives:

d = (185 - 150) / 6 = 35 / 6 = 5.83

So, the Cohen's d effect size is approximately 5.83.

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